What are the vertical and horizontal asymptotes for the function f of x is equal to the fraction with numerator x squared plus x minus 6 and denominator x cubed minus 1 ?

Factor the denominator: x³ − 1 = (x − 1)(x² + x + 1). The numerator factors as (x + 3)(x − 2), so there is no cancellation at x = 1; this gives the vertical asymptote x = 1. Since the denominator’s degree is greater than the numerator’s, the horizontal asymptote is y = 0. Therefore, choice B is correct.

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