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8
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Practice Test

Question 8 • Chemistry

A tire at 21 times degree C has a pressure of 0 point 8 2 atm. Its temperature decreases to negative 3 point 5 times degree C If there is no volume change in the tire, what is the pressure after the temperature change? Use the fraction with numerator cap p sub 1 and denominator cap t sub 1 is equal to the fraction with numerator cap p sub 2 and denominator cap t sub 2

Answer
A
1 point 3 atm
B
1 point 1 atm
C
0 point 7 5 atm
D
0 point 8 9 atm

Explanation

With the tire’s volume unchanged, pressure is proportional to absolute temperature, so convert Celsius to kelvins before using P₁/T₁ = P₂/T₂. The temperatures are 21°C = 294.15 K and −3.5°C = 269.65 K. Thus P₂ = 0.82 × (269.65 ÷ 294.15) ≈ 0.75 atm, which is choice C, 0.75 atm.

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