Question 2 • Algebra II
Subtract (x + 2)/x from both sides: 3 + 4/x − (x + 2)/x ≥ 0. Combine the fractions and write 3 as 3x/x, giving (3x + 4 − x − 2)/x = (2x + 2)/x ≥ 0, with x ≠ 0. This matches choice D, the fraction with numerator 2x + 2 and denominator x.
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