AnswersFL-1200700-Mathematics for College Algebra MISSolving Linear Equations: Variables on Both Sides

Solving Linear Equations: Variables on Both Sides — Unit test Answers

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3

Which is a correct first step in solving 5 – 2x < 8x – 3?

A
5 < 6x – 3
B
3x < 8x – 3
C
5 < 10x – 3
D
2 – 2x < 8x
4

Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?

A
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the left.
Option A
B
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
Option B
C
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the left.
Option C
D
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the right.
Option D
5

Step 1: Subtract 3 from both sides of the inequality.Step 2: __________Step 3: Divide both sides of the inequality by the coefficient of x.

A
Add 2x to both sides of the inequality.
B
Subtract 8x from both sides of the inequality.
C
Subtract 2x from both sides of the inequality.
D
Add 8x to both sides of the inequality.
7

Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Select three options.1 ≥ 2x6x ≥ 3 + 8x – 4

Question illustration
A
1 ≥ 2x
B
6x ≥ 3 + 8x – 4
C
A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at 0.5 and a bold line starts at 0.5 and is pointing to the left.
Option C
D
A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at negative 0.5 and a bold line starts at negative 0.5 and is pointing to the right.
Option D
E
A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at 0.5 and a bold line starts at 0.5 and is pointing to the right.
Option E
9

Which is a correct first step in solving the inequality –4(2x – 1) > 5 – 3x?

A
Distribute –4 to get –8x + 4 > 5 – 3x.
B
Distribute –4 to get –8x – 1 > 5 – 3x.
C
Subtract 2x from both sides of the inequality.
D
Add 1 to both sides of the inequality.
10

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.x < 5–6x – 5 < 10 – x–6x + 15 < 10 – 5x

Question illustration
A
x < 5
B
–6x – 5 < 10 – x
C
–6x + 15 < 10 – 5x
D
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
Option D
E
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
Option E

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