A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring?

Elastic potential energy is given by U = ½kx². Rearranging gives x = √(2U/k) = √(2 × 5184 / 16,200) = √0.64 = 0.80 m. Therefore, the displacement is 0.80 m, choice C.

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