A twirler’s baton is 0.76 m long and spins around its center. The end of the baton has a centripetal acceleration of 47.8 m/s2.

The baton’s end moves in a circle with radius half its length: r = 0.76/2 = 0.38 m. Using centripetal acceleration, a = ω²r, gives ω = √(47.8/0.38) ≈ 11.2 rad/s. The period is T = 2π/ω ≈ 0.56 s, so the correct choice is 0.56 s.

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