Question 3 • Mathematics II
Because the order of the three students does not matter, use combinations: 7 choose 3 = 7! ÷ (4! × 3!). Simplifying gives (7 × 6 × 5) ÷ (3 × 2 × 1) = 35, so 35 different groups are possible. The correct choice is C, 35.
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