Answers KISD SS-3391B-Algebra II Honors BGraphing Logarithmic Functions

Properties of Logarithms Answers

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A student solved the equation below by graphing.Which statement about the graph is true?

The curves do not intersect.

The curves intersect at one point.

The curves intersect at two points.

The curves appear to coincide.

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What is the approximate value of x in the equation below.

–3.396

–0.708

0.304

0.955

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a 1 and b 1?

StartFraction log Subscript b Baseline x Over log Subscript b Baseline a EndFraction

StartFraction log Subscript b Baseline a Over log Subscript b Baseline x EndFraction

StartFraction log Subscript a Baseline b Over log Subscript x Baseline b EndFraction

StartFraction log Subscript a Baseline x Over log Subscript b Baseline x EndFraction

Consider the equation below.Which system of equations can represent the equation?

y 1 = StartFraction log (x + 3) Over log 4 EndFraction, y 2 = StartFraction log (2 + x) Over log 2 EndFraction

y 1 = StartFraction log x + 3 Over log 4 EndFraction, y 2 = StartFraction log 2 + x Over log 2 EndFraction

y 1 = StartFraction log 4 Over log 2 EndFraction, y 2 = StartFraction log (x + 3) Over log (2 + x) EndFraction

y 1 = StartFraction log x + 3 Over 4 EndFraction, y 2 = StartFraction log 2 + x Over 2 EndFraction

Tyler applied the change of base formula to a logarithmic expression. The resulting expression is shown below. Which expression could be Tyler’s original expression?

Log Subscript one-fourth Baseline 12

Log Subscript 12 Baseline One-fourth

12 Log one-fourth

One-fourth log 12

Which system of equations could be graphed to solve the equation below?

y 1 = 3 x, y 2 = 2 x

y 1 = log (2 x + 1), y 2 = 3 x minus 2

y 1 = log 2 x + 1, y 2 = 3 x minus 2

y 1 = log (2 x + 1 + 2), y 2 = 3 x

Devonte used the change of base formula to approximate . Which expression did Devonte use?

Log StartFraction 8 Over 25 EndFraction

StartFraction log 8 Over log 25 EndFraction

log StartFraction 25 Over 8 EndFraction

StartFraction log 25 Over log 8 EndFraction

Which is equivalent to ?

log n = StartFraction log 2 Over 4 EndFraction

n = StartFraction log 2 Over log 4 EndFraction

n = log 4 times log 2

log n = 4 log 2

A teacher used the change of base formula to determine whether the equation below is correct.Which statement explains whether the equation is correct?

The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log (2 times 10) times log (4 times 8) times log (10 times 4). = log (20) times log (32) times log (40). =3

The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = StartFraction log 10 Over log 2 EndFraction times StartFraction log 8 Over log 4 EndFraction times StartFraction log 4 Over log 10 EndFraction. = StartFraction log 8 Over log 2 EndFraction. = 3

The equation is not correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log StartFraction 10 Over 2 EndFraction times log eight-fourths times log four-tenths. = log 5 times log 2 times log 0.4. = negative 0.08

What is the approximate value of q in the equation below?

–1.613

–1.522

0.585

3.079

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Properties of Logarithms Answers

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