Given the quadratic function f⁡(x)=2⁢x^2−8⁢x+6 , what is the vertex of the function?

For f(x)=2x²−8x+6, the vertex’s x-coordinate is −b/(2a)=−(−8)/(2·2)=2. Substituting x=2 gives f(2)=2(2²)−8(2)+6=−2. Therefore, the vertex is (2, −2), choice B.

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