Given the quadratic function f⁡(x)=−4⁢(x+3)^2+7 , what is the range of the function?

The function is in vertex form, f(x) = −4(x + 3)² + 7, so its vertex is (−3, 7). Because the coefficient −4 is negative, the parabola opens downward and its highest value is 7. Therefore, the range is y ≤ 7, which is choice A.

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