Given the quadratic function f⁡(x)=2⁢x^2−8⁢x+6 , find the vertex and use x=0 to calculate another point on the graph.

For f(x) = 2x² − 8x + 6, the vertex’s x-coordinate is −b/(2a) = −(−8)/(2·2) = 2. Substituting x = 2 gives f(2) = 8 − 16 + 6 = −2, so the vertex is (2, −2). At x = 0, f(0) = 6, giving the point (0, 6), which matches choice A.

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