Answers NHS Algebra I Integrated Math II Semester 2 CRQuadratic Functions: Standard Form

Quadratic Functions: Standard Form Answers

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The graph of which function has a y-intercept of 3?

On a coordinate plane, a parabola opens up. It goes through (negative 3, 3), has a vertex at (negative 1.5, 0.75), and goes through (0, 3).

On a coordinate plane, a parabola opens up. It goes through (1, 4), has a vertex at (3, 0), and goes through (5, 4).

On a coordinate plane, a parabola opens up. It goes through (negative 5, 4), has a vertex at (negative 3, 0), and goes through (negative 1, 4).

On a coordinate plane, a parabola opens up. It goes through (negative 4, 5), has a vertex at (negative 1, negative 4), and goes through (2, 5).

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Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Select three options.The domain is {x|x ≤ –2}.The range is {y|y ≤ 6}.The function is increasing over the interval (–∞ , –2).The function is decreasing over the interval (−4, ∞).The function has a positive y-intercept.

The domain is {x|x ≤ –2}.

The range is {y|y ≤ 6}.

The function is increasing over the interval (–∞ , –2).

The function is decreasing over the interval (−4, ∞).

The function has a positive y-intercept.

What is the x-intercept of the graph of the function f(x) = x2 − 16x + 64?

(−8, 0)

(0, 8)

(8, 0)

(0, −8)

The axis of symmetry for the graph of the function f(x)=3x2+bx+4 is . What is the value of b?

−18

−9

Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Select two options.

The domain of the function is .

The range of the function is all real numbers.

The vertex of the function is .

The function has two x-intercepts.

The function is increasing over the interval (, ∞).

On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0).

(–6, 0), (2,0)

(–2, –16), (0, –12)

(–6, 0), (–2, –16), (2, 0)

(0, –12), (–6, 0), (2, 0)

Tempestt graphs a function that has a maximum located at (–4, 2). Which could be her graph?

On a coordinate plane, a parabola opens up. It goes through (negative 6, 6), has a vertex at (negative 4, 2), and goes through (negative 2, 6).

On a coordinate plane, a parabola opens up. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6).

On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 2), has a vertex at (negative 4, 2), and goes through (negative 2, negative 2).