Use substitution to write an equivalent quadratic equation.(3x + 2)2 + 7(3x + 2) – 8 = 0u² + 7u - 8 = 0, where u = (3x + 2)²u² + 7u - 8 = 0, where u = 3x + 2u² + 7u - 8 = 0, where u = 7(3x + 2)u² + u - 8 = 0
Select all of the zeroes of the function.
Factor. (u + 16)(u + 1) = 0(u - 16)(u - 1) = 0(u + 17)(u - 1) = 0
What are the solutions of the original equation?x = 1 or x = –2x = –1 or x = 2x = –5 or x = –2x = 4 or x = –5
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