Answers AISD Algebra II B Credit Recovery 2026-2027Division of Polynomials

Quadratic in Form Polynomials Answers

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What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

x = StartFraction negative 3 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction

x = StartFraction 7 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction

x = 2

x = 8

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Which equation is quadratic in form?

4(x – 2)2 + 3x – 2 + 1 = 0

8x5 + 4x3 + 1 = 0

10x8 + 7x4 + 1 = 0

9x16 + 6x4 + 1 = 0

Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0?

u2 – 11u + 24 = 0 where u = (x2 – 1)

(u2)2 – 11(u2) + 24 where u = (x2 – 1)

u2 + 1 – 11u + 24 = 0 where u = (x2 – 1)

(u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)

Which quadratic equation is equivalent to (x – 4)2 – (x – 4) – 6 = 0?

(u – 4)2 – (u – 4) – 6 = 0 where u = (x – 4)

u2 – (u – 4) – 6 = 0 where u = (x – 4)

u2 – 16 – u – 6 = 0 where u = (x – 4)

u2 – u – 6 = 0 where u = (x – 4)

What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?

u = (x3)

u = (x3 + 1)

u = (x3 + 1)2

u = (x3 + 1)3

What are the solutions of the quadratic equation (x – 8)2 – 13(x – 8) + 30 = 0? Use u substitution to solve.

x = –11 and x = –18

x = –2 and x = 5

x = 2 and x = –5

x = 11 and x = 18

What are the solutions of the equation x4 + 3x2 + 2 = 0? Use u substitution to solve.

and x = ±1

and x = ±i

and x = ±1

What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) – 4 = 0 as a quadratic equation?

u = (x + 5)

u = (x – 5)

u = (x + 5)2

u = (x – 5)2

What substitution should be used to rewrite 4x12 – 5x6 – 14 = 0 as a quadratic equation?

u = x2

u = x3

u = x6

u = x12

What are the solutions of the equation x4 – 5x2 – 14 = 0? Use factoring to solve.

and

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Quadratic in Form Polynomials Answers

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