AnswersAlgebra 2 - Semester 1 PathwaysQuadratic in Form PolynomialsQuestion 1
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Quadratic in Form Polynomials

Question 1 • Algebra 2 - Semester 1 Pathways

Which equation is equivalent tof(x) = 16x4 – 81 = 0?(4x² - 9)(4x² - 9) = 0✔ (4x² + 9)(4x² - 9) = 0(4x - 9)(4x - 9) = 0(4x + 9)(4x - 9) = 0

Answer
A
(4x² - 9)(4x² - 9) = 0
B
✔ (4x² + 9)(4x² - 9) = 0
C
(4x - 9)(4x - 9) = 0
D
(4x + 9)(4x - 9) = 0
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