Using the quadratic formula to solve 4 x squared minus 3 x plus 9 is equal to 2 x plus 1 , what are the values of x ?

First move all terms to one side: 4x² − 3x + 9 = 2x + 1 becomes 4x² − 5x + 8 = 0. Using the quadratic formula, x = (5 ± √((-5)² − 4·4·8))/(2·4) = (5 ± √(−103))/8. Since √(−103) = i√103, the solutions are (5 ± i√103)/8, which is choice C.

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