Question 2 • Algebra II
For a square root to be real, the expression inside it must be at least 0. Here the radicand is x − 5, so x − 5 ≥ 0, which gives x ≥ 5; the multiplier 2 does not change the domain. Therefore, the domain is x greater than or equal to 5.
AI-written and checked against the verified answer.