Question 3 • 4413VA ALGEBRA 3 SEM A
Solve each inequality separately because they are joined by “or.” From 3x + 7 ≤ 4x − 8, subtract 3x and add 8 to get x ≥ 15. From −2x + 3 ≥ 1, subtract 3 and divide by −2, reversing the inequality, to get x ≤ 1. The solution is x ≤ 1 or x ≥ 15, which is choice A.
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