Solve: x = –4x = 4x = –4 or x = 4no real solution

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[___] in.
9
Do you agree with the student? Explain why or why not.I do not agree with the student because there is no real solution.Checking the solutions in the original equation verifies ; however, is extraneous.Checking the solutions in the original equation shows that 6 is an extraneous solution.I agree with the student because both and satisfy the original equation.
Solve:

Solve:

⇒ 8 in.
9
Do you agree? Explain why or why not.

I do not agree with the student. While solving the equation results in x 4, this is an extraneous solution. When you substitute 4 back into the original equation, you get sqrt(2(4) 1) 3 0, which simplifies to 3 3 0, or 6 0. Since this is a false statement, x 4 is not a solution. Furthermore, the equation sqrt(2x 1) 3 has no real solution because a principal square root cannot be negative.
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Do you agree with the student? Explain why or why not.




Solve: s = 2s = 7s = 2 or s = 7no real solution

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Solve:

Solve:





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