Solve: The solution is a =

1/6
Solve and check The solution is c =

14
After multiplying each side of the equation by the LCD and simplifying, the resulting equation is X 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.
x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.
Question text not available



Name the true solution(s) to the equation.X x = 0x = 1x = 8x = 0, x = 1, and x = 8✔ x = 1 and x = 8There are no solutions.
Question text not available
No, the student is incorrect. When solving the equation, the algebraic solution found is a = –2. However, this value must be checked against the restrictions of the original equation. Substituting –2 into the denominators (a + 2) and (a^2 – 4) results in division by zero, which is undefined. Therefore, a = –2 is an extraneous solution, and the original rational equation actually has no solution.
Which of the following did you include in your answer?
Question text not available




What are the solutions to the equation?



Name the extraneous solution(s) to the equation.✔ x = 0x = 1x = 8x = 0, x = 1, and x = 8X x = 1 and x = 8There are no extraneous
Did you find these answers helpful?