Question 18 • Algebra II
First note that x cannot equal 0 because it is in the denominator. Rewrite the inequality as (x² − 36)/(4x) ≤ 0; the critical values are −6, 0, and 6. Checking the intervals shows the expression is nonpositive for x ≤ −6 and for 0 < x ≤ 6. Thus the solution is (−∞, −6] ∪ (0, 6], shown by choice D.
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