AnswersVOA Math MN-Algebra I with Quadratics CR 2BLinear Piecewise Defined Functions

Reflections and Dilations of Absolute Value Functions Answers

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1
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The function shown is reflected across the y-axis to create a new function.

Question illustration
A
Both the domain and range change.
B
Both the range and domain stay the same.
C
The domain stays the same, but the range changes.
D
The range stays the same, but the domain changes.
2
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Question text not available

Question illustration
A
f(x) = –|x|
B
f(x) = |–x|
C
f(x) = |x| + 1
D
f(x) = |x – 1|
3

Which graph represents the function f(x) = –|x + 3|?

A
Option
B
Option
C
Option
D
Option
4

Question text not available

Question illustration
A
f(x) = −|x − 3| + 4
B
f(x) = −|x + 3| + 4
C
f(x) = −|x − 4| + 3
D
f(x) = −|x + 4| + 3
5

Question text not available

Question illustration
A
f(x) = –|x| + 1
B
f(x) = –|x – 1|
C
f(x) = |–x| + 1
D
f(x) = |–x – 1|
6

Which graph represents the function f(x) = |x|?

Question illustration
A
Option
B
Option
C
Option
D
Option
7

Question text not available

Question illustration
A
f(x) = 1.3|x| – 2
B
f(x) = 3|x – 2|
C
f(x) = |x – 2|
Option C
D
f(x) = |x| + 2
Option D
8

Question text not available

Question illustration
A
f(x) = |x| – 3
B
f(x) = |x + 2|
C
f(x) = 0.5|x|
D
f(x) = 4|x|
9

The absolute value function, f(x) = |x + 2|, is shown.

Question illustration
A
all real numbers
B
all real numbers greater than or equal to 0
C
all real numbers greater than or equal to –2
D
all real numbers less than or equal to –2
10

Question text not available

Question illustration
A
f(x) = –|x| + 4
B
f(x) = –|x| – 4
C
f(x) = –|x + 4|
D
f(x) = –|x – 4|

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