Secants, Tangents, and Angles Answers

The perimeter of a square is 56 cm. What is the approximate length of its diagonal?

In circle D, ∠EDH ≅ ∠EDG.

Rhombus LMNO is shown with its diagonals.

Circle D is shown with the measures of the minor arcs.

Parallelogram W X Y Z is shown. Diagonals are drawn from point W to point Y and from point Z to point X and intersect at point C. The length of W C is (x + 4) feet and the length of C Y is (2 x minus 7) feet.

Line segment SU is a diameter of circle V.

Circle D is inscribed with triangle A B C. The measure of arc A B is 76 degrees. Point E is on the circle between points B and C.

In parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, andOP = (2x – 1) m.

ABCD is a square.

Parallelogram R S T U is shown. Angle S is 70 degrees.

Quadrilateral A B D C is shown.

EFGH is a rhombus.

Circle D is shown. Angle A C B intercepts arc A B. Arc A B has a measure of 76 degrees.

Line segment KL is tangent to circle J at point K.

Circle T is shown. Angle Q S R intercepts arc Q R. Angle Q S R is 52 degrees.

In circle T, ∠PTQ ≅ ∠RTS.

Parallelogram A B C D is shown. The length of A B is (9 x minus 14) inches and the length of D C is (3 x + 4) inches.

Given: Circle M with inscribed and congruent radii JM and MLProve: m =

The figure shown is a rhombus.

Rhombus LMNO is shown with its diagonals.

Line segment TS is tangent to circle O at point N.

Parallelogram A B C D is shown. The length of A B is (8 x minus 5) inches and the length of D C is (3 x + 10) inches.

In circle N, KL ≅ ML.

is tangent to circle G at point F.

Given: AD ≅ BC and AD ∥ BCProve: ABCD is a parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC 1. given 2. ∠CAD and ∠ACB are alternate interior ∠s 2. definition of alternate interior angles 3. ∠CAD ≅ ∠ACB 3. alternate interior angles are congruent 4. AC ≅ AC 4. reflexive property 5. △CAD ≅ △ACB 5. SAS congruency theorem 6. AB ≅ CD 6. ? 7. ABCD is a parallelogram 7. parallelogram side theorem What is the missing reason in step 6?