We are given line segment AB is parallel to line segment DE Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal line segment CB and are therefore congruent, so angle CED is congruent to angle CBA We can state angle cap c is congruent to angle cap c using the reflexive property. Therefore, triangle ACB approximates triangle DCE by the
To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that
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