Data were recorded for a car’s fuel efficiency, in miles per gallon (mpg), and corresponding speed, in miles per hour (mph). Given the least-squares regression line, the natural log of open paren widehat Fuel Efficiency close paren is equal to 1 point 4 3 7 plus 0 point 5 4 1 ln Speed , what is the fuel efficiency for a speed of 60 mph?
Substitute 60 for Speed: ln(predicted fuel efficiency) = 1.437 + 0.541 ln(60) ≈ 3.652. Since the model gives the natural log of fuel efficiency, exponentiate: e^3.652 ≈ 38.55 mpg. The correct choice is 38.55 mpg.
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