Both are extraneous solutions.Only 3 is an extraneous solution. Only –3 is an extraneous solution. Neither is an extraneous solution.
Explain the error in the solution below. What additional step needs to be completed?log x – log53 = 2log53 log x = 3log53 log x = log533 x = 27
The error in the solution is treating the logarithms as if they have the same base. The first term, log x, is a common logarithm (base 10), while the other terms have a base of 5. The one-to-one property of logarithms only applies when the bases are identical. To solve the equation correctly, you must first use the change-of-base formula to rewrite the logarithms so they have the same base before attempting to equate the arguments.
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Which statement is true about the potential solution x = –5?
Which equation can you solve to find the potential solutions to the equation log2x + log2(x – 6) = 4?
What is the solution to log7(x – 4) = log7(4x + 5) ?
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5
Which equation can you solve to find the potential solutions to the equation log2x + log2(x – 6) = 4?
What is the solution to log7(x – 4) = log7(4x + 5) ?
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3
Which of the following did you include in your response?
Both are extraneous solutions.Only 3 is an extraneous solution. Only –3 is an extraneous solution. Neither is an extraneous solution.
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1
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