AnswersPBCSD_Grade_Forgiveness_1200330_Algebra 2_S1_2024Radical Equations and Extraneous Roots

Solving Equations using Properties of Logarithms Answers

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1
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Maria wrote the equation What is the solution to Maria’s equation?

Question illustration
A
x = three-tenths
Option A
B
x = four-fifths
Option B
C
x = five-fourths
Option C
D
x = ten-thirds
Option D
2
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Which of the following illustrates the product rule for logarithmic equations?

A
log Subscript 2 Baseline (4 x) = log Subscript 2 Baseline 4 divided by log Subscript 2 Baseline x
Option A
B
log Subscript 2 Baseline (4 x) = log Subscript 2 Baseline 4 times log Subscript 2 Baseline x
Option B
C
log Subscript 2 Baseline (4 x) = log Subscript 2 Baseline 4 minus log Subscript 2 Baseline x
Option C
D
log Subscript 2 Baseline (4 x) = log Subscript 2 Baseline 4 + log Subscript 2 Baseline x
Option D
3

What is the solution to

Question illustration
A
x = negative 8
Option A
B
x = negative 3
Option B
C
x = 3
Option C
D
x = 8
Option D
4

Which of the following is true regarding the solutions to the logarithmic equation below?

Question illustration
A
and are true solutions
Option A
B
and are extraneous solutions
Option B
C
is an extraneous solution and is a true solution
Option C
D
is a true solution and is an extraneous solution
Option D
5

What is the true solution to the logarithmic equation below?

Question illustration
A
x = 2
Option A
B
x = 8
Option B
C
x = 64
Option C
D
x = 128
Option D
6

Which of the following is true regarding the solutions to the logarithmic equation below?

Question illustration
A
and are true solutions
Option A
B
and are extraneous solutions
Option B
C
is a true solution and is an extraneous solution
Option C
D
is an extraneous solution and is a true solution
Option D
7

Which of the following shows the true solution to the logarithmic equation below?

Question illustration
A
x = negative 3
Option A
B
x = 4
Option B
C
and
Option C
D
and
Option D
8

Which of the following shows the equation rewritten using logarithms?

Question illustration
A
4 Superscript log Subscript 4 Baseline (x + 6) Baseline = 2 squared
Option A
B
4 Superscript log Subscript 4 Baseline (x + 6) Baseline = 4 Superscript 4
Option B
C
log Subscript 4 Baseline (x + 6) = log Subscript 4 Baseline 16
Option C
D
log Subscript 4 Baseline (x + 6) = log Subscript 2 Baseline 16
Option D
9

What is the solution to

Question illustration
A
x = six-nineteenths
Option A
B
x = eight-nineteenths
Option B
C
x = 7
Option C
D
x = 8
Option D
10

What is the solution to

Question illustration
A
x = negative 8
Option A
B
x = negative 4
Option B
C
x = 4
Option C
D
x = 8
Option D

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