AnswersPBCSD_Grade_Forgiveness_1200330_Algebra 2_S2_2024Graphing Logarithmic Functions

Solving Equations using Properties of Logarithms Answers

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Sam is proving the product property of logarithms. StepJustificationGivenSubstitution Which expression and justification completes the third step of her proof?

Question illustration
A
; power rule of exponents
Option A
B
subtraction property of exponents
Option B
C
multiplication rule of exponents
Option C
D
division property of exponents
Option D
2
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What is rewritten using the power property?

Question illustration
A
log Subscript 15 Baseline 5
Option A
B
log Subscript 15 Baseline 6
Option B
C
2 log Subscript 15 Baseline 3
Option C
D
3 log Subscript 15 Baseline 2
Option D
3

What is written as a single logarithm?

Question illustration
A
log Subscript 5 Baseline (25 x Superscript 5 Baseline) RootIndex 3 StartRoot x squared + 6 EndRot
Option A
B
log Subscript 5 Baseline (25 x Superscript 6 Baseline) RootIndex 3 StartRoot x squared + 6 EndRoot
Option B
C
log Subscript 5 Baseline 25 x Superscript 5 Baseline + log Subscript 5 Baseline 2 + log one-third x squared
Option C
D
(log Subscript 5 Baseline 25 + log Subscript 5 Baseline Superscript 6 Baseline) (log Subscript 5 Baseline RootIndex 3 StartRoot x squared + 6 EndRoot)
Option D
4

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as , where and is the least intense sound a human ear can hear. Brandon is trying to take a nap, and he can barely hear his neighbor mowing the lawn. The sound intensity level that Brandon can hear is 10-10. Ahmad, Brandon’s neighbor that lives across the street, is mowing the lawn, and the sound intensity level of the mower is 10-4. How does Brandon’s sound intensity level compare to Ahmad’s mower?

Question illustration
A
Brandon’s sound intensity is the level of Ahmad’s mower.
Option A
B
Brandon’s sound intensity is the level of Ahmad’s mower.
Option B
C
Brandon’s sound intensity is 20 times the level of Ahmad’s mower.
D
Brandon’s sound intensity is 80 times the level of Ahmad’s mower.
5

Given and , what is ?

Question illustration
A
1.404
B
1.739
C
2.773
D
2.988
6

Which expression is equivalent to ?

Question illustration
A
log Subscript 12 Baseline 8 minus log Subscript 12 Baseline one-half + log Subscript 12 Baseline w
Option A
B
log Subscript 12 Baseline one-half minus (log Subscript 12 Baseline 8 + log Subscript 12 Baseline w)
Option B
C
log Subscript 12 Baseline one-half minus log Subscript 12 Baseline 8 + log Subscript 12 Baseline w
Option C
D
log Subscript 12 Baseline one-half divided by log Subscript 12 Baseline 8 + log Subscript 12 Baseline w
Option D
7

The table shows a student’s proof of the quotient rule for logarithms.Let M = bx and N = by for some real numbers x and y. StepReason1Given2Substitution3Properties of logarithms4Logarithm property logb(bc) = c5SubstitutionWhat is the error in the proof?

Question illustration
A
The error is in step 3. The reason should be the quotient property of exponents.
B
The error is in step 3. You cannot use a property of logarithms to prove that same property.
C
The error is in step 2. The reason should be the quotient property of exponents.
D
The error is in step 5. The student did not convert from exponential to logarithmic form correctly when solving for x and y.
8

Which expression is equivalent to log18 – log(p + 2)?

A
log StartFraction p + 2 Over 18 EndFraction
Option A
B
log StartFraction 18 Over p + 2 EndFraction
Option B
C
log StartFraction 20 Over p EndFraction
Option C
D
log left-bracket 18 times (p + 2) right-bracket
Option D
9

Which expression is equivalent to ?

Question illustration
A
log Subscript 3 Baseline c + log Subscript 3 Baseline (9)
Option A
B
log Subscript 3 Baseline (9) + log Subscript 3 Baseline (c)
Option B
C
log Subscript 3 Baseline c minus log Subscript 3 Baseline (9)
Option C
D
log Subscript 3 Baseline (9) minus log Subscript 3 Baseline (c)
Option D
10

Which expression is equivalent to log3(x + 4)?

A
log3 – log(x + 4)
B
log12 + logx
C
log3 + log(x + 4)
D
StartFraction log 3 Over log (x + 4) EndFraction
Option D

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