Solving Linear Equations: Variable on One Side Answers

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On a coordinate plane, 2 lines are shown. Line M N goes through (negative 4, 8) and (negative 4, negative 6). Line K L goes through (negative 8, 2) and (6, 2).

Question illustration
A
The lines intersect at point K.
B
The lines are parallel.
C
The lines are perpendicular.
D
The lines do not have slopes.
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The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form of the equation for this line?

Question illustration
A
y – 3 = –(x + 8)
Option A
B
y + 3 = –(x – 8)
Option B
C
y + 8 = –(x – 3)
Option C
D
y – 8 = –(x + 3)
Option D
23

Determine the missing information in the paragraph proof.Given: Line PQ is rotated 90° counterclockwise to form line P’Q’. The lines are perpendicular. Line PQ contains the points (a, b) and (c, d). Line P’Q’ contains the points (–b, a) and (–d, c).Prove: The slopes of perpendicular lines are negative reciprocals.

Question illustration
A
(StartFraction d minus b Over c minus a EndFraction) (StartFraction c minus a Over negative d + b EndFraction) = negative 1
Option A
B
(StartFraction b minus a Over a + b EndFraction) (StartFraction c minus d Over negative d minus c EndFraction) = negative 1
Option B
C
(StartFraction d minus b Over c minus a EndFraction) (StartFraction c minus a Over negative d + b EndFraction) = 1
Option C
D
(StartFraction b minus a Over a + b EndFraction) (StartFraction c minus d Over negative d minus c EndFraction) = 1
Option D
24

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is . What is the standard form of the equation for this line?

Question illustration
A
2x – 5y = –15
B
2x – 5y = –17
C
2x + 5y = –15
D
2x + 5y = –17
25

The ice skating rink charges an hourly fee for skating and $3 to rent skates for the day. Gillian rented skates and skated for 3 hours and was charged $21. Which equation represents the cost, c(x), of ice skating as a function of x, the number of hours of skating?

A
c(x) = 3x + 3
B
c(x) = 6x + 3
C
c(x) = 7x + 3
D
c(x) = 8x + 3

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