–2.8760–0.34770.71241.3738
The expression is the result of applying the change of base formula to a logarithmic expression. Which could be the original expression?

Which graph shows the solution to the equation log2(3x – 1) = 2?
Graph a system of equations to approximate the value of x, the rate of depreciation. Give your answer as a percent.
What are the approximate solutions of the equation? Check all that apply.
Question text not available
x ≈ [___] and x ≈ [___].
Cannot be determined from the provided information
–2.8760–0.34770.71241.3738
The expression is the result of applying the change of base formula to a logarithmic expression. Which could be the original expression?





Which graph shows the solution to the equation log2(3x – 1) = 2?




Graph a system of equations to approximate the value of x, the rate of depreciation. Give your answer as a percent.
What are the approximate solutions of the equation? Check all that apply.




Question text not available
Elsa tries to solve the following equation, and determines there is no solution. Is she correct? Explain. log2x = log2(3x + 5) + 4
Elsa is correct; there is no solution. To solve the equation $\log_2(x) = \log_2(3x + 5) + 4$, first combine the logarithmic terms: $\log_2(x) - \log_2(3x + 5) = 4$, which simplifies to $\log_2(\frac{x}{3x + 5}) = 4$. Converting to exponential form gives $\frac{x}{3x + 5} = 2^4 = 16$. Solving for $x$: $x = 16(3x + 5) \implies x = 48x + 80 \implies -47x = 80 \implies x = -\frac{80}{47}$. However, in the original equation, the domain for $\log_2(x)$ requires $x > 0$. Since $x = -\frac{80}{47}$ is negative, it is an extraneous solution. Because this is the only potential solution, the equation has no real solution.
2.3219–0.4307–2.32190.4307
x ≈ [___] and x ≈ [___].
Cannot be determined from the provided information
2.3219–0.4307–2.32190.4307
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