Solving Logarithmic Equations using Technology Answers
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1
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Omar wants to use a graph to solve the equation below.Which system of equations should Omar use?
A
y 1 = StartFraction log 6 Over x EndFraction , y 2 = StartFraction log 2 Over x + 4 EndFraction
B
y 1 = StartFraction log x Over log 6 EndFraction, y 2 = StartFraction log x + 4 Over log 2 EndFraction
C
y 1 = StartFraction log 6 Over log 2 EndFraction, y 2 = StartFraction log x Over log (x + 4) EndFraction
D
y 1 = StartFraction log x Over log 6 EndFraction, y 2 = StartFraction log (x + 4) Over log 2 EndFraction
2
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What is the approximate value of x in the equation below?
A
–2.523B
–1.317C
2.880D
7.4853
A teacher used the change of base formula to determine whether the equation below is correct.Which statement explains whether the equation is correct?
A
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log (2 times 10) times log (4 times 8) times log (10 times 4). = log (20) times log (32) times log (40). =3
B
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = StartFraction log 10 Over log 2 EndFraction times StartFraction log 8 Over log 4 EndFraction times StartFraction log 4 Over log 10 EndFraction. = StartFraction log 8 Over log 2 EndFraction. = 3
C
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = StartFraction log 10 Over log 2 EndFraction times StartFraction log 8 Over log 4 EndFraction times StartFraction log 4 Over log 10 EndFraction. = StartFraction log 8 Over log 2 EndFraction. = 4.
D
The equation is not correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log StartFraction 10 Over 2 EndFraction times log eight-fourths times log four-tenths. = log 5 times log 2 times log 0.4. = negative 0.08
4
Tenisha solved the equation below by graphing a system of equations.Which point approximates the solution for Tenisha’s system of equations?
A
(0.9, 0.8)B
(1.0, 1.4)C
(2.3, 1.1)D
(2.7, 13.3)5
Which is equivalent to ?
A
log n = StartFraction log 2 Over 4 EndFraction
B
n = StartFraction log 2 Over log 4 EndFraction
C
n = log 4 times log 2
D
log n = 4 log 2
6
Kim solved the equation below by graphing a system of equations.What is the approximate solution to the equation?
A
0.6B
0.9C
1.4D
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