AnswersAZ-Algebra 1A MA101Solving One-Variable Inequalities

Solving One-Variable Inequalities Answers

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What value of x is in the solution set of the inequality 8x – 6 > 12 + 2x?

A
–1
B
0
C
3
D
5
2
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Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?

A
A number line from negative 7 to 7 in increments of 1. A point is at negative 5 and a bold line starts at negative 5 and is pointing to the right.
Option A
B
A number line from negative 7 to 7 in increments of 1. A point is at 5 and a bold line starts at 5 and is pointing to the right.
Option B
C
A number line from negative 7 to 7 in increments of 1. A point is at 5 and a bold line starts at 5 and is pointing to the left.
Option C
D
A number line from negative 7 to 7 in increments of 1. A point is at negative 5 and a bold line starts at negative 5 and is pointing to the right.
Option D
3

Step 1: Subtract 3 from both sides of the inequality.Step 2: __________Step 3: Divide both sides of the inequality by the coefficient of x.

A
Add 2x to both sides of the inequality.
B
Subtract 8x from both sides of the inequality.
C
Subtract 2x from both sides of the inequality.
D
Add 8x to both sides of the inequality.
4

Which number line represents the solution set for the inequality –x ≥ 4?

Question illustration
A
A number line from negative 10 to 10 in increments of 2. A point is at negative 2 and a bold line starts at negative 2 and is pointing to the left.
Option A
B
A number line from negative 10 to 10 in increments of 2. A point is at negative 8 and a bold line starts at negative 8 and is pointing to the left.
Option B
C
A number line from negative 10 to 10 in increments of 2. A point is at negative 2 and a bold line starts at negative 2 and is pointing to the right.
Option C
D
A number line from negative 10 to 10 in increments of 2. A point is at negative 8 and a bold line starts at negative 8 and is pointing to the right.
Option D
5

Solve the inequality.2(4+2x)≥5x+5

A
x≤−2
B
x≥−2
C
x≤3
D
x≥3
6

Which is a correct first step in solving the inequality –4(2x – 1) > 5 – 3x?

A
Distribute –4 to get –8x + 4 > 5 – 3x.
B
Distribute –4 to get –8x – 1 > 5 – 3x.
C
Subtract 2x from both sides of the inequality.
D
Add 1 to both sides of the inequality.
7

What value of x is in the solution set of the inequality –5x – 15 > 10 + 20x?

A
–2
B
–1
C
0
D
1
8

What value of x is in the solution set of the inequality 2(3x – 1) ≥ 4x – 6?

A
–10
B
–5
C
–3
D
–1
9

What value of x is in the solution set of the inequality 4x – 12 ≤ 16 + 8x?

A
–10
B
–9
C
–8
D
–7
10

Which is a correct first step in solving 5 – 2x < 8x – 3?

A
5 < 6x – 3
B
3x < 8x – 3
C
5 < 10x – 3
D
2 – 2x < 8x

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