AnswersPBCSD_Grade_Forgiveness_1200330_Algebra 2_S1_2024Solving Polynomial Equations using Technology

Solving Polynomial Equations using Technology Answers

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5

Which equation can be solved by using this system of equations?

Question illustration
A
3 x cubed minus 7 x squared + 5 = 0
Option A
B
3 x cubed minus 7 x squared + 5 = 7 x Superscript 4 Baseline + 2 x
Option B
C
7 x Superscript 4 Baseline + 2 x = 0
Option C
D
7 x Superscript 4 Baseline + 3 x cubed minus 7 x squared + 2 x + 5 = 0
Option D
6

Which system of equations can be used to find the roots of the equation ?

Question illustration
A
StartLayout Enlarged left-brace 1st Row y = negative 4 x Superscript 5 Baseline + 12 x Superscript 4 Baseline minus 6 x 2nd row y = 5 x cubed minus 2 x EndLayout
Option A
B
StartLayout Enlarged left-brace 1st Row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 5 x cubed + 4 x 2nd row y = 0 EndLayout
Option B
C
StartLayout Enlarged left-brace 1st row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 6x 2nd row y = negative 5 x cubed + 2 x EndLayout
Option C
D
StartLayout Enlarged left-brace 1st row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 6x 2nd row y = 5 x cubed minus 2 x EndLayout
Option D
7

Which system of equations can be used to find the roots of the equation ?

Question illustration
A
StartLayout Enlarged left-brace 1st row y = negative 4 x squared 2nd row y = x cubed + 2 x EndLayout
Option A
B
StartLayout Enlarged left-brace 1st row y = x cubed + 4 x squared + 2 x 2nd row y = 0 EndLayout
Option B
C
StartLayout Enlarged left-brace 1st row y = 4 x squared 2nd row y = negative x cubed minus 2 x EndLayout
Option C
D
StartLayout Enlarged left-brace 1st row 4 x squared 2nd row y = x cubed + 2 x EndLayout
Option D
8

The graph of this system of equations is used to solve . What represents the solution set?

Question illustration
A
y-intercepts of the graph
B
x-intercepts of the graph
C
y-coordinates of the intersection points
D
x-coordinates of the intersection points

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