AnswersPBCSD_Grade_Forgiveness_1200330_Algebra 2_S1_2024Solving Polynomial Equations with Complex Solutions

Solving Polynomial Equations with Complex Solutions Answers

10 verified answers
1
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Find all the solutions to 3x3 – 6x2 + 30x – 20 = –20.

A
0, 1 + 3i, 1 – 3i
B
0, 2 + 6i, 2 – 6i
C
0, –1 + 3i, –1 – 3i
D
0, –2 + 6i, –2 – 6i
2
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Find all solutions to the equation x3 + 100x + 8x2 = –800.

A
–10, –8, 10
B
–10, 8, 10
C
8, –10i, 10i
D
–8, –10i, 10i
3

Consider the equation 3x3 + 14x2 – 14x + 60 = 0. The real solution is –6. What are the nonreal solutions?

A
Negative 2 i StartRoot 26 EndRoot, 2 i StartRoot 26 EndRoot.
Option A
B
4 minus 2 i StartRoot 26 EndRoot, 4 + 2 i StartRoot 26 EndRoot.
Option B
C
StartFraction negative 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction negative 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.
Option C
D
StartFraction 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.
Option D
4

Find all solutions to the equation 3x3 + 12x = 2x2 + 8.

A
Negative 2, negative two-thirds, 2.
Option A
B
Negative 2, two-thirds, 2.
Option B
C
Negative two-thirds, negative 2 i, 2 i.
Option C
D
Two-thirds, negative 2 i, 2 i.
Option D
5

What are the solutions to –24x – 24 = x3 + 8x2?

A
Negative 1, negative 3 + i StartRoot 3 EndRoot, negative 3 minus i StartRoot 3 EndRoot.
Option A
B
1, 3 + i StartRoot 3 EndRoot, 3 minus i StartRoot 3 EndRoot.
Option B
C
2, 3 + i StartRoot 3 EndRoot, 3 minus i StartRoot 3 EndRoot.
Option C
D
Negative 2, negative 3 + i StartRoot 3 EndRoot, negative 3 minus i StartRoot 3 EndRoot.
Option D
6

What are all the roots, both real and nonreal, of the equation x4 + x2 = 4x2 + 4?

A
Negative one-half, one-half, negative 2 i, 2 i.
Option A
B
Negative one-half, one-half, negative i, i.
Option B
C
Negative 1, 1, negative 2 i, 2 i.
Option C
D
Negative 2, 2, negative i, i.
Option D
8

On a coordinate plane, a curve goes through (negative 6, 0), has a maximum at (negative 5, 500), decreases to (negative 2.5, negative 450), increases through (0, negative 50), increases again through (1, 0), and then goes through (2, 400).

Question illustration
A
StartFraction 1 + i StartRoot 5 EndRoot Over 3 EndFraction, StartFraction 1 minus i StartRoot 5 EndRoot Over 3 EndFraction.
Option A
B
StartFraction negative 1 + i StartRoot 5 EndRoot Over 3 EndFraction, StartFraction negative 1 minus i StartRoot 5 EndRoot Over 3 EndFraction.
Option B
C
StartFraction negative 1 + StartRoot 5 EndRoot Over 3 EndFraction, StartFraction negative 1 minus StartRoot 5 EndRoot Over 3 EndFraction.
Option C
D
StartFraction 1 + StartRoot 5 EndRoot Over 3 EndFraction, StartFraction 1 minus StartRoot 5 EndRoot Over 3 EndFraction.
Option D
9

On a coordinate plane, a curve goes through (negative 2, 0), has a minimum point at (negative 1, negative 40), increases through (0, negative 20), has an inflection point at (1.5, 0), and then increases.

Question illustration
A
Negative 2, 2, StartFraction negative 3 minus i Over 2 EndFraction, StartFraction negative 3 + i Over 2 EndFraction.
Option A
B
Negative 20, StartFraction 3 minus i Over 2 EndFraction, StartFraction 3 + i Over 2 EndFraction.
Option B
C
Negative 2, 2, StartFraction 3 minus i Over 2 EndFraction, StartFraction 3 + i Over 2 EndFraction.
Option C
D
Negative 20, StartFraction negative 3 minus i Over 2 EndFraction, StartFraction negative 3 + i Over 2 EndFraction.
Option D
10

Find all the solutions to the equation 4x3 + 16x2 + 28x = 0.

A
0, negative 4 + 2 i StartRoot 3 EndRoot, negative 4 negative 2 i StartRoot 3 EndRoot
Option A
B
0, 4 + 2 i StartRoot 3 EndRoot, 4 minus 2 i StartRoot 3 EndRoot
Option B
C
0, negative 2 + i StartRoot 3 EndRoot, negative 2 minus i StartRoot 3 EndRoot
Option C
D
0, 2 + StartRoot 3 EndRoot, 2 minus i StartRoot 3 EndRoot
Option D

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