AnswersFL-1200330-Algebra 2 Sem 1 - FlexSolving Quadratic Equations by Factoring

Solving Quadratic Equations by Factoring Answers

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3

Which equation has solutions of 6 and -6?

A
x2 – 12x + 36 = 0
B
x2 + 12x – 36 = 0
C
x2 + 36 = 0
D
x2 – 36 = 0
5

What are the solutions of 8x2 = 6 + 22x? Check all of the boxes that apply.

A
x = -3
B
x =
Option B
C
x = 3
D
x = 6
16

Which equation represents the situation? 2w² - w + 28 = 0✔ 2w² - w - 28 = 0X 2w² + w - 28 = 02w² + w + 28 = 0

A
2w² - w + 28 = 0
B
✔ 2w² - w - 28 = 0
C
X 2w² + w - 28 = 0
D
2w² + w + 28 = 0
18

What did you include in your response? Check all of the boxes that apply.

A
Peta can only use the zero product property when the product of factors is equal to zero.
B
Peta must multiply x by (x - 5).
C
Peta must write the equation in standard form, then factor the expression.
D
Each factor must be set equal to zero, not 20.
21

Peta attempted to solve the following equation. Explain Peta's error. x (x - 5) = 20 x = 20 and x - 5 = 20 x = 20 and x = 25

Answer:

Peta cannot set x and x − 5 each equal to 20 because their product is 20, not zero. The zero-product property does not apply. The equation is quadratic and its solutions are (5 + √105)/2 and (5 − √105)/2.

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