AnswersFL-1200710-Mathematics for College Algebra ASolving Quadratic Equations: Completing the Square (Continued)

Solving Quadratic Equations: Completing the Square (Continued) Answers

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Tran is solving the quadratic equation 2x2 – 4x – 3 = 0 by completing the square. His first four steps are shown in the table.

Question illustration
A
Step 1
B
Step 2
C
Step 3
D
Step 4
2
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Sienna is solving the quadratic equation by completing the square.3x2 + 9x – 4 = 0 3x2 + 9x = 4 A(x2 + 3x) = 4

A
–4
B
–3
C
3
D
4
3

Maya is solving the quadratic equation by completing the square.4x2 + 16x + 3 = 0

A
Isolate the variable x2.
B
Subtract 16x from both sides of the equation.
C
Isolate the constant.
D
Factor 4 out of the variable terms.
4

Atraeus is solving the quadratic equation by completing the square.7x2 – 14x + 6 = 0 7x2 – 14x = –6 A(x2 – 2x) = –6

A
–14
B
2
C
6
D
7
5

Gio is solving the quadratic equation by completing the square.5x2 + 15x – 4 = 0

A
Isolate the constant.
B
Factor 5 out of the variable terms.
C
Isolate the variable x.
D
Add 9 to both sides of the equation.
6

Sunil is solving the quadratic equation by completing the square.6x2 + 24x + 5 = 06x2 + 24x = –5

A
Isolate the variable x2.
B
Isolate the constant.
C
Factor 6 out of the variable terms.
D
Subtract 24x from both sides of the equation.
7

What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15?

A
x = –1 – and x = –1 +
Option A
B
x = –1 – and x = –1 +
Option B
C
x = 1 – and x = 1 +
Option C
D
x = 1 – and x = 1 +
Option D
8

What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

A
x = –4 – and x = –4 +
Option A
B
x = –4 – and x = –4 +
Option B
C
x = –4 – and x = –4 +
Option C
D
x = –4 – and x = –4 +
Option D
9

The first few steps in solving the quadratic equation 8x2 + 80x = −5 by completing the square are shown.8x2 + 80x = −58(x2 + 10x) = −58(x2 + 10x + 25) = −5 + ______

A
−200
B
−25
C
25
D
200
10

What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

A
x = –1 – and x = –1 +
Option A
B
x = –1 – and x = –1 +
Option B
C
x = –1 – and x = –1 +
Option C
D
x = –1 – and x = –1 +
Option D

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