AnswersFL-1200330-Algebra 2 Sem 1 - FlexSolving Quadratic Equations by Factoring

Solving Quadratic Equations: Square Root Property Answers

13 verified answers
81850
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4✔ 81632

Answers:
x =:8
x =:–8
81851

–32–16✔ –8–4

A
–32
B
–16
C
✔ –8
D
–4
81852

What are the solutions of the quadratic equation 49x2 = 9?

A
x = [image 1] and x = [image 2]
Option A
B
x = [image 1] and x = [image 2]
Option B
C
x = [image 1] and x = [image 2]
Option C
D
x = [image 1] and x = [image 2]
Option D
81853

What are the roots of f(x) = x2 – 48?

A
–48 and 48
Option A
B
–24 and 24
Option B
C
[image 1] and [image 2]
Option C
D
[image 1] and [image 2]
Option D
81854

What are the possible values of x if (4x – 5)2 = 49? Check all that apply. [image 1] [image 2] 357

Question illustration
A
Option
Option A
B
Option
Option B
C
3
D
5
E
7
81855

Solve for x if 2(5x + 2)2 = 48.

A
x = [image 1] and x = [image 2]
Option A
B
x = [image 1] and x = [image 2]
Option B
C
x = [image 1] and x = [image 2]
Option C
D
x = [image 1] and x = [image 2]
Option D
81858

2024✔ 3649

A
20
B
24
C
✔ 36
D
49
81859

–16–88✔ 16

Answers:
Sonya found that x = is one solution of (6x + 4)2 = . The other solution is x = .:16
Sonya found that x = is one solution of (6x + 4)2 = . The other solution is x = .:0
81860

✔ 02/34/34

A
✔ 0
B
2/3
C
4/3
D
4
81861

Analyze Marika’s steps. Which statement is true about her work?

A
In step 2, Marika should have simplified [image 1] to be [image 2] .
Option A
B
There are no real solutions to this equation because the square root of a negative number is not a real number.
Option B
C
There should be two real solutions to this equation because [image 1] = [image 2] .
Option C
D
Marika correctly solved this equation.
Option D

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