Solve the quadratic equation numerically (using tables of x- and y- values).x(x + 3) = 0

Rewrite the equation as y = x(x + 3). The solutions are the x-values where y = 0, which occur when either factor is zero: x = 0 or x + 3 = 0, giving x = -3. A table of values would show y = 0 at those two x-values, so the correct choice is “x = 0 or x = -3.”

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