Solving Systems of Linear Equations: Graphing Answers

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y=–x + 4x + 2y=–8

Question illustration
A
one solution: (8, 0)
B
one solution: (0, 8)
C
no solution
D
infinite number of solutions
2
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What is the solution to the system of equations?2x – y = 7y = 2x + 3

A
(2, 3)
B
(2, 7)
C
no solution
D
infinite number of solutions
3

A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFraction 5 over 2 EndFraction and passes through the (0, 2.5) and (2.2, negative 1.4). The second line is labeled y equals StartFraction 3 over 4 EndFraction x minus 3 and passes through (0, negative 3, 0.14) and (2.2, negative 1.4)

Question illustration
A
(0.33, 1)
B
(1.33, 1)
C
(1.83, 1)
D
(2.33, 1)
4

How many solutions does this linear system have?y = 2x – 5 –8x – 4y = –20

A
one solution: (–2.5, 0)
B
one solution: (2.5, 0)
C
no solution
D
infinite number of solutions
5

A system of equations has no solution. If y = 8x + 7 is one of the equations, which could be the other equation?

A
2y = 16x +14
B
y = 8x – 7
C
y = –8x + 7
D
2y = −16x − 14
6

Sylvie finds the solution to the system of equations by graphing.y = x + 1 and y = x – 1Which graph shows the solution to Sylvie’s system of equations?

Question illustration
A
Option
B
Option
C
Option
D
Option
7

Billy graphed the system of linear equations to find an approximate solution.y = x + y = x – 3Which points are possible approximations for this system? Select two options.(1.9, 2.5)(2.2, –1.4)(2.2, –1.35)(1.9, 2.2)(1.9, 1.5)

Question illustration
A
(1.9, 2.5)
B
(2.2, –1.4)
C
(2.2, –1.35)
D
(1.9, 2.2)
E
(1.9, 1.5)
8

A coordinate grid with 2 lines. The first line labeled f(x) passes through (negative 3, 3), (0, 2), and (3, 1). The second line labeled g(x) passes through the points at (negative 3, 0) and (0, 2)

Question illustration
A
(–3, 0)
B
(–3, 3)
C
(0, 2)
D
(3, 1)
9

Which values of m and b will create a system of equations with no solution? Select two options.y = mx + b y = –2x + m = –3 and b = m = –2 and b = m = 2 and b = m = and b = m = -2 and b =

Question illustration
A
m = –3 and b =
Option A
B
m = –2 and b =
Option B
C
m = 2 and b =
Option C
D
m = and b =
Option D
E
m = -2 and b =
Option E
10

y=–6x+2–12x – 2y=–4

A
one solution: (0, 0)
B
one solution: (1, –4)
C
no solution
D
infinite number of solutions

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