AnswersAISD Algebraic Reasoning B Credit Recovery 2026-2027Solving Systems of Linear Equations: Substitution

Solving Systems of Linear Equations: Substitution Answers

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1
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y=–3x + 6y=9

A
(–21, 9)
B
(9, –21)
C
(–1, 9)
D
(9, –1)
2
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y=–5x + 30x=10

A
(–20, 10)
B
(10, –20)
C
(10, 4)
D
(4, 10)
3

What is the solution to the system of equations?y = 1.5x – 4y = –x

A
(–1.6, 1.6)
B
(–1.5, 1.5)
C
(1.5, –1.5)
D
(1.6, –1.6)
4

Ernesto tried to determine the solution for the system of equations using substitution. His work is shown below.x – y = 73x – 2y = 8Step 1: x = y + 7Step 2: 3(y + 7) – 2y = 8Step 3: 3y + 7 – 2y = 8Step 4: y + 7 = 8Step 5: y = 1

A
Step 1
B
Step 2
C
Step 3
D
Step 4
5

The tables represent two linear functions in a system.What is the solution to this system?

Question illustration
A
(1, 0)
B
(1, 6)
C
(8, 26)
D
(8, –22)
6

y=–5x + 30x=10

A
(–20, 10)
B
(10, –20)
C
(10, 4)
D
(4, 10)
7

What is the solution to the system of equations?y = 1.5x – 4y = –x

A
(–1.6, 1.6)
B
(–1.5, 1.5)
C
(1.5, –1.5)
D
(1.6, –1.6)
8

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?y = -2x + 46x + 3y =

Question illustration
A
-12
B
-4
C
4
D
12
9

The tables represent two linear functions in a system.What is the solution to this system?

Question illustration
A
(negative StartFraction 13 over 3 EndFraction, negative 25)
Option A
B
(negative StartFraction 14 over 3 EndFraction, negative 54)
Option B
C
(–13, –50)
D
(–14, –54)
10

What is the solution to the system of equations?y = x + 3x = –2

Question illustration
A
(negative 2, negative StartFraction 15 over 2 EndFraction)
Option A
B
(negative 2, StartFraction 5 over 3 EndFraction)
Option B
C
(negative 2, StartFraction 11 over 6 EndFraction)
Option C
D
(negative 2, StartFraction 13 over 3 EndFraction)
Option D

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