Answers PrecalculusSolving Trigonometric Inequalities

Solving Trigonometric Inequalities Answers

0 verified answers

Free Preview

What is the solution to the trigonometric inequality over the interval radians?

and

and

and

and

Free Preview

To solve the trigonometric inequality , Carl graphed the equations and . Shelly, on the other hand, took the cube root of both sides of the inequality so that it became , and she then graphed the equations and . Which of the following statements is true regarding the points of intersection of Carl’s graph and Shelly’s graph?

The points of intersection of Carl’s graph have different x-coordinates than the points of intersection of Shelly’s graph and different y-coordinates.

The points of intersection of Carl’s graph have different x-coordinates than the points of intersection of Shelly’s graph but the same y-coordinates.

The points of intersection of Carl’s graph have the same x-coordinates as the points of intersection of Shelly’s graph but different y-coordinates.

The points of intersection of Carl’s graph have the same x-coordinates as the points of intersection of Shelly’s graph and the same y-coordinates.

Which trigonometric inequality has no solution over the interval radians?

cosecant (x) minus 1 is greater than 0

cosine (x) minus 1 is greater than 0

cotangent (x) minus 1 is greater than 0

tangent (x) minus 1 is greater than 0

The graph below can be used to help solve which of the following trigonometric inequalities over the interval radians?

5 cosine (x) minus 7.5 is greater than equal to 6 cosine (x) minus 7

5 sine (x) minus 7.5 is greater than equal to 6 sine (x)minus 7

5 sine (x) minus 7 is greater than equal to 6 cosine (x) minus 7.5

5 sine (x) minus 7 is greater than equal to 6 sine (x) minus 7.5

Which half of the unit circle satisfies the trigonometric inequality ? Assume that is the angle made by the positive x-axis and a ray from the origin.

the top half

the bottom half

the right half

the left half

Which of the following is part of the solution to the trigonometric inequality over the interval radians?

StartFraction pi over 6 EndFraction

StartFraction pi over 2 EndFraction

StartFraction 2 pi over 3 EndFraction

StartFraction 3 pi over 2 EndFraction

The graph below can be used to help solve which of the following trigonometric inequalities over the interval radians?

cosine (x) is greater than equal to minus 1

cosine (x) minus sine (x) is greater than equal to minus 1

sine (x) is greater than equal to minus 1

sine (x) minus cosine (x) is greater than equal to minus 1

To help solve the trigonometric inequality , which two equations can be graphed?

and

The graph below can be used to help solve which of the following trigonometric inequalities over the interval radians?

sine (x) minus 1 is less than equal to cosine (2x) minus 2

sine (x) minus 1 is less than equal to cosine (2x) plus 2

sine (2x) minus 1 is less than equal to cosine (x) minus 2

sine (2x) minus 1 is less than equal to cosine (x) plus 2

To help solve the trigonometric inequality , Tracey successfully graphed the equations and with her graphing calculator. Which of the following statements is true about the inequality?

There is no solution because even though you cannot see it, the graph of the equation is above the graph of the equation for all values of x.

There is no solution because the graph of the equation is the same as the graph of the equation , so is never below .

There are an infinite number of solutions because even though you cannot see it, the graph of the equation is below the graph of the equation for all values of x.

There are an infinite number of solutions because the graph of the equation is the same as the graph of the equation , so is never below .

Did you find these answers helpful?

Solving Trigonometric Inequalities Answers

More from this Course

TRY EDGENUITY HACKS