AnswersMathematics III ASquare Root Functions

Square Root Functions Answers

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1
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If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot x minus 3 EndRoot greater-than-or-equal-to 0
Option A
B
x minus 3 greater-than-or-equal-to 0
Option B
C
StartRoot x minus 3 EndRoot less-than-or-equal-to 0
Option C
D
x minus 3 less-than-or-equal-to 0
Option D
2
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What is the domain of the square root function graphed below?

Question illustration
A
x less-than-or-equal-to negative 1
Option A
B
x greater-than-or-equal-to negative 1
Option B
C
x less-than-or-equal-to 0
Option C
D
x greater-than-or-equal-to 0
Option D
3

What is the domain of the square root function graphed below?

Question illustration
A
x greater-than 1
Option A
B
x greater-than-or-equal-to 10
Option B
C
x greater-than 3
Option C
D
x greater-than-or-equal-to 3
Option D
4

Which equation is the inverse of y = 100 – x2?

A
y = plus-or-minus StartRoot 100 minus x EndRoot
Option A
B
y = 10 plus-or-minus StartRoot x EndRoot
Option B
C
y = 100 plus-or-minus StartRoot x EndRoot
Option C
D
y = plus-or-minus StartRoot x minus 100 EndRoot
Option D
5

If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot one-half x EndRoot greater-than-or-equal-to 0
Option A
B
One-half x greater-than-or-equal-to 0
Option B
C
One-half x minus 10 greater-than-or-equal-to 0
Option C
D
StartRoot one-half x minus 10 EndRoot + 3 greater-than-or-equal-to 0
Option D
6

If the domain of the square root function f(x) is , which statement must be true?

Question illustration
A
7 is subtracted from the x-term inside the radical.
B
The radical is multiplied by a negative number.
C
7 is added to the radical term.
D
The x-term inside the radical has a negative coefficient.
7

Which equation can be simplified to find the inverse of y = 5x2 + 10?

A
x = 5y2 + 10
B
StartFraction 1 Over y EndFraction = 5 x squared + 10
Option B
C
–y = 5x2 + 10
D
y = one-fifth x squared + one-tenth
Option D
8

Which equation is the inverse of ?

Question illustration
A
y = one-fifth x squared + six-fifths x + eleven-tenths
Option A
B
y = 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot
Option B
C
Negative 5 y minus 4 = negative (x + 3) squared minus one-half
Option C
D
y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot
Option D
9

Which equation can be simplified to find the inverse of y = 2x2?

A
StartFraction 1 Over y EndFraction = 2 x squared
Option A
B
y = one-half x squared
Option B
C
–y = 2x2
D
x = 2y2
10

Which equation is the inverse of 2(x – 2)2 = 8(7 + y)?

A
–2(x – 2)2 = –8(7 + y)
B
y = one-fourth x squared minus x minus 6
Option B
C
y = negative 2 plus-or-minus StartRoot 28 + 4 x EndRoot
Option C
D
y = 2 plus-or-minus StartRoot 28 + 4 x EndRoot
Option D

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