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Square Root Functions Answers

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Which equation is the inverse of y = 2x2 – 8?

A
y = plus-or-minus StartRoot StartFraction x + 8 Over 2 EndFraction EndRoot
Option A
B
y = StartFraction plus-or-minus StartRoot x + 8 EndRoot Over 2 EndFraction
Option B
C
y = plus-or-minus StartRoot StartFraction x Over 2 EndFraction + 8 EndRoot
Option C
D
y = StartFraction plus-or-minus StartRoot x EndRoot Over 2 EndFraction + 4
Option D
2
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Which equation can be simplified to find the inverse of y = x2 – 7?

A
x = y squared minus one-seventh
Option A
B
StartFraction 1 Over x EndFraction = y squared minus 7
Option B
C
x = y2 – 7
D
–x = y2 – 7
3

What is the domain of the square root function graphed below?

Question illustration
A
x less-than-or-equal-to negative 1
Option A
B
x greater-than-or-equal-to negative 1
Option B
C
x less-than-or-equal-to 0
Option C
D
x greater-than-or-equal-to 0
Option D
4

Which equation is the inverse of 2(x – 2)2 = 8(7 + y)?

A
–2(x – 2)2 = –8(7 + y)
B
y = one-fourth x squared minus x minus 6
Option B
C
y = negative 2 plus-or-minus StartRoot 28 + 4 x EndRoot
Option C
D
y = 2 plus-or-minus StartRoot 28 + 4 x EndRoot
Option D
5

If the domain of the square root function f(x) is , which statement must be true?

Question illustration
A
7 is subtracted from the x-term inside the radical.
B
The radical is multiplied by a negative number.
C
7 is added to the radical term.
D
The x-term inside the radical has a negative coefficient.
6

Which could be the function graphed below?

Question illustration
A
f (x) = StartRoot x EndRoot minus 2
Option A
B
f (x) = StartRoot x minus 3 EndRoot + 1
Option B
C
f (x) = StartRoot 2x + 4 EndRoot
Option C
D
f (x) = StartRoot x + 1 EndRoot + 8
Option D
7

Which equation can be simplified to find the inverse of y = 2x2?

A
StartFraction 1 Over y EndFraction = 2 x squared
Option A
B
y = one-half x squared
Option B
C
–y = 2x2
D
x = 2y2
8

Which equation is the inverse of y = 16x2 + 1?

A
y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot
Option A
B
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 16 EndFraction
Option B
C
y = StartFraction plus-or-minus StartRoot x EndRoot Over 4 EndFraction minus one-fourth
Option C
D
y = StartFraction plus-or-minus StartRoot x minus 1 EndRoot Over 4 EndFraction
Option D
9

Which equation can be simplified to find the inverse of y = 5x2 + 10?

A
x = 5y2 + 10
B
StartFraction 1 Over y EndFraction = 5 x squared + 10
Option B
C
–y = 5x2 + 10
D
y = one-fifth x squared + one-tenth
Option D
10

If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot x minus 3 EndRoot greater-than-or-equal-to 0
Option A
B
x minus 3 greater-than-or-equal-to 0
Option B
C
StartRoot x minus 3 EndRoot less-than-or-equal-to 0
Option C
D
x minus 3 less-than-or-equal-to 0
Option D

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