The chemical equation shows the combustion of propane open paren cap c sub 3 cap h sub 8 close paren cap c sub 3 cap h sub 8 plus 5 cap o sub 2 rightarrow 3 CO sub 2 plus 4 cap h sub 2 cap o The molar mass of oxygen gas open paren cap o sub 2 close paren is 32 point 0 0 g over mol The molar mass of cap c sub 3 cap h sub 8 is 44 point 1 g over mol What mass of cap o sub 2 , in grams, is required to completely react with 0 point 0 2 5 g cap c sub 3 cap h sub 8 ?
Convert the propane mass to moles: 0.025 g ÷ 44.1 g/mol ≈ 0.000567 mol. The balanced equation requires 5 mol of O₂ for every 1 mol of propane, so this needs about 0.00283 mol O₂. Its mass is 0.00283 mol × 32.00 g/mol ≈ 0.091 g, so the correct choice is 0.091 grams.
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