AnswersFL-1200330-Algebra 2 Sem 1 - FlexComposition of Functions

Symmetry Answers

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31
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Answer:

3

44
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Answer:

-2

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-1

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-2

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-3

64

evenoddneither

Question illustration
A
even
B
odd
C
neither
65

g(x) = |x-3| evenoddneither

A
even
B
odd
C
neither
66

evenoddneither

Question illustration
A
even
B
odd
C
neither
67

g(x) = x + x² evenoddneither

A
even
B
odd
C
neither
82

(f • g)(x) =evenoddneither

A
even
B
odd
C
neither
84

(g • g)(x) = evenoddneither

A
even
B
odd
C
neither
86

The function is increasingdecreasingconstant for –9 < x < –7.

A
increasing
B
decreasing
C
constant
87

The function is increasing for –3 < x < 0 –7 < x < –3–9 < x < –7.

A
–3 < x < 0
B
–7 < x < –3
C
–9 < x < –7
88

The point (–5, 8)(–5, –8)(5, –8) lies on the graph of the function.

A
(–5, 8)
B
(–5, –8)
C
(5, –8)
92

Dimetri says that a function that is made of terms where the variable is raised only to an odd power will be an odd function. Do you agree with Dimetri? Explain why or why not.

Answer:

Dimetri is correct only if there is no constant term. Replacing x with −x changes the sign of every term with an odd power, but it does not change a constant. Therefore, the function is odd only when there is no constant term.

93

Compare your response to the sample response above. Did your explanation

A
state that the function will be odd only if there is no constant term?
B
state that raising -x to an odd power results in -x?
C
state that the terms with variables will be opposites but the constant won’t?

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Lesson 2.4: Composition of Functions