Figure WXYZ is transformed using the rule . Point W of the pre-image is at (1, 6).

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime F prime G prime H prime is shifted down to E double-prime F double-prime G double-prime H double-prime.

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On a coordinate plane, 2 triangles are shown. Triangle J K L has points (2, negative 4), (5, negative 4), (2, negative 2). Triangle J double-prime K double-prime L double-prime has points (2, 2), (2, 5), (0, 2).





The rule is applied to ΔFGH to produce ΔF"G"H".

The rule is applied to ΔABC.

Trapezoid G H J K is rotated about G 90 degrees counterclockwise to form trapezoid G prime H prime J prime K prime. Trapezoid G prime H prime J prime K prime is reflected across the line of reflection m to form trapezoid G double-prime H double-prime J double-prime K double-prime.

Which ordered pairs name the coordinates of vertices of the pre-image, trapezoid ABCD? Select two options.
Square A"B"C"D" is the final image after the rule was applied to square ABCD.

Parallelogram F"G"H"J" is the final image after the rule was applied to parallelogram FGHJ.

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7).

On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime has points (negative 1, 4), (negative 1, 2), (negative 5, 3). Triangle B double-prime C double-prime D double-prime has points (5, negative 1), (5, negative 3), (1, negative 2).





A composition of transformations maps ΔXYZ to ΔX"Y"Z".

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