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Synthetic Division and the Remainder Theorem Answers

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If (x + 8) is a factor of f(x), which of the following must be true?

A
Both x = –8 and x = 8 are roots of f(x).
B
Neither x = –8 nor x = 8 is a root of f(x).
C
f(–8) = 0
D
f(8) = 0
2
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If –1 is a root of f(x), which of the following must be true?

A
A factor of f(x) is (x – 1).
B
A factor of f(x) is (x + 1).
C
Both (x – 1) and (x + 1) are factors of f(x).
D
Neither (x – 1) nor (x + 1) is a factor of f(x).
3

What divisor is represented by the synthetic division below?

Question illustration
A
–5
B
5
C
x + 5
D
x – 5
4

Use synthetic division to solve . What is the quotient?

Question illustration
A
4 x squared minus 27 x + 167 minus StartFraction 996 Over x minus 6 EndFraction
Option A
B
4 x squared + 21 x + 131 + StartFraction 792 Over x + 6 EndFraction
Option B
C
4 x squared + 21 x + 131 + StartFraction 792 Over x minus 6 EndFraction
Option C
D
4 x squared minus 27 x + 167 minus StartFraction 996 Over x + 6 EndFraction
Option D
5

What remainder is represented by the synthetic division below?

Question illustration
A
–5
B
0
C
1
D
2
6

One root of is x = 2. What are all the roots of the function? Use the Remainder Theorem.

Question illustration
A
x = 2, x = 3, or x = 4
B
x = –2, x = –3, or x = –4
C
x = 1, x = 2, x = 3, or x = 13
D
x = –1, x = –2, x = –3, or x = –13
7

Use synthetic division to solve (x3 + 1) ÷ (x – 1). What is the quotient?

A
x squared + x + 1 + StartFraction 2 Over x + 1 EndFraction
Option A
B
x squared minus x + 1
Option B
C
x squared + x + 1 + StartFraction 2 Over x minus 1 EndFraction
Option C
D
x cubed minus x squared + x minus 1
Option D
8

If f(1) = 0, what are all the roots of the function ? Use the Remainder Theorem.

Question illustration
A
x = –1, x = 1, or x = 3
B
x = –3, x = –1, or x = 1
C
x = –3 or x = 1
D
x = –1 or x = 3
9

What dividend is represented by the synthetic division below?

Question illustration
A
Negative 10 x squared minus 5
Option A
B
2 x cubed + 10 x squared + x + 5
Option B
C
2 x squared + 1
Option C
D
2 x cubed + x
Option D
10

Use synthetic division to solve . What is the quotient?

Question illustration
A
3 x cubed + 12 x squared + 26 x + 61 + StartFraction 132 Over x + 2 EndFraction
Option A
B
3 x cubed + 2 x + 5
Option B
C
3 x cubed + 12 x squared + 26 x + 61 + StartFraction 132 Over x minus 2 EndFraction
Option C
D
3 x Superscript 4 Baseline + 2 x squared + 5 x
Option D

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