AnswersFall 24 GMS Geometry Concepts and Connections BSolving for Angle Measures of Right Triangles

Solving for Angle Measures of Right Triangles — Test Answers

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6

The equation can be used to find the length of .

Question illustration
1
14.3 in.
2
20.5 in.
2
21.3 in.
2
22.6 in.
7

Law of sines:

Question illustration
A
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (76 degrees) Over z EndFraction
Option A
B
StartFraction sine (51 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option B
C
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (51 degrees) Over z EndFraction
Option C
D
StartFraction sine (76 degrees) Over 2.6 EndFraction = StartFraction sine (53 degrees) Over z EndFraction
Option D
10

Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
72 = 82 + 112 – 2(8)(11)cos(N)
B
82 = 72 + 112 – 2(7)(11)cos(M)
C
72 = 82 + 112 – 2(8)(11)cos(P)
D
82 = 72 + 112 – 2(7)(11)cos(P)
14

The equation can be used to find the length of .

Question illustration
A
3.0 cm.
B
9.8 cm.
C
10.5 cm.
D
12.8 cm.

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