Testing a Claim about a Mean Difference Answers

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1
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Select the correct "state” portion of the hypothesis test.

A
H0: μwithout OJ = μwith OJ H0: μwithout OJ > μwith OJ where μwithout OJ = the true mean heart rate without drinking OJ and μwith OJ = the true mean heart rate after drinking OJ.
B
H0: μwithout OJ = μwith OJ Ha: μwithout OJ < μwith OJ where μwithout OJ = the true mean heart rate without drinking OJ and μwith OJ = the true mean heart rate after drinking OJ.
C
H0: μdiff = 0 Ha: μdiff < 0 Where μdiff = the true mean difference (withoutOJ − with OJ) in heart rates for students like these.
D
H0: μdiff = 0 Ha: μdiff > 0 Where μdiff = the true mean difference (withoutOJ − with OJ) in heart rates for students like these.
2
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✔ met-randomized experimentmet-randomly selectednot metnot needed

A
✔ met-randomized experiment
B
met-randomly selected
C
not met
D
not needed
3

metnot met✔ not needed

A
met
B
not met
C
✔ not needed
4

population is Normaln is at least 30✔ graph: not skewed, no outliers

A
population is Normal
B
n is at least 30
C
✔ graph: not skewed, no outliers
5

a decreasean increase✔ a difference

A
a decrease
B
an increase
C
✔ a difference
167622

Check the 3 conditions for inference:

Answers:
Name::One-sample t-test for mean diff
Random::met-randomly selected
10%: 30 < 10% of .:all sets of twins in the database
Normal/Large Sample: met because .:n is at least 30
167623

met-randomized experiment✔ met-randomly selectednot metnot needed

A
met-randomized experiment
B
✔ met-randomly selected
C
not met
D
not needed
167626

Perform the calculations, then complete the conclusion.

Answers:
Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.:between 0.10 and 0.20
Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.:greater than
Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.:fail to reject
Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.:do not have
Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.:a difference
167628

✔ fail to rejectreject

A
✔ fail to reject
B
reject
167631

Perform the calculations, then complete the conclusion.

Answers:
Because the P-value we calculated is = 0.05, we H0. We convincing evidence to believe that the batteries their ability, on average, to hold a charge during the first year.:is less than
Because the P-value we calculated is = 0.05, we H0. We convincing evidence to believe that the batteries their ability, on average, to hold a charge during the first year.:reject
Because the P-value we calculated is = 0.05, we H0. We convincing evidence to believe that the batteries their ability, on average, to hold a charge during the first year.:have
Because the P-value we calculated is = 0.05, we H0. We convincing evidence to believe that the batteries their ability, on average, to hold a charge during the first year.:do lose
167632

✔ rejectfail to reject

A
✔ reject
B
fail to reject
167633

do not have✔ have

A
do not have
B
✔ have
167634

do not lose✔ do losekeepdo not keep

A
do not lose
B
✔ do lose
C
keep
D
do not keep

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