Testing a Claim about a Mean Difference Answers

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1
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Researchers wonder if practicing yoga reduces stress levels in adults. They select a random sample of 32 adults and assess their current stress levels. The participants are told to practice 60 minutes of yoga each day for one week. At the end of the week, their stress levels are assessed again. The mean difference (pre-yoga – post-yoga) in stress scores is 2.68 points with a standard deviation of 5.58 points. A positive value indicates that the subject’s stress level decreased.

A
Because the P-value is less than α, there is evidence that practicing yoga is associated with lower stress levels, on average, in adults like the ones in the study.
B
Because the P-value is greater than α, there is evidence that practicing yoga is associated with lower stress levels, on average, in adults like the ones in the study.
C
Because the P-value is less than α, there is not sufficient evidence that practicing yoga is associated with lower stress levels, on average, in adults like the ones in the study.
D
Because the P-value is greater than α, there is not sufficient evidence that practicing yoga is associated with lower stress levels, on average, in adults like the ones in the study.
2
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A nurse at a local hospital wonders if the firstborn twin is taller than the second-born. He randomly selects the medical records of 33 sets of twins and finds the differences (firstborn – second-born) in the twins’ heights, in centimeters. The mean of the differences is 1.1 centimeters with a standard deviation of 2.3 centimeters. Assuming that the conditions for inference are met, what is the test statistic for testing the hypotheses ?

Question illustration
A
t = StartStartFraction 0 minus 1.1 OverOver StartFraction 2.3 Over StartRoot 33 EndRoot EndFraction EndEndFraction
Option A
B
t = StartStartFraction 0 minus 1.1 OverOver StartRoot StartFraction 2.3 Over 33 EndFraction EndRoot EndEndFraction
Option B
C
t = StartStartFraction 1.1 minus 0 OverOver StartFraction 2.3 Over StartRoot 33 EndRoot EndFraction EndEndFraction
Option C
D
t = StartStartFraction 1.1 minus 0. OverOver StartRoot StartFraction 2.3 Over 33 EndFraction EndRoot EndEndFraction
Option D
3

A statistics teacher is interested in whether there is a difference in the accuracy of dominant versus nondominant hands. She asks her students to roll a ball, once with each hand, toward a target. The students then measure the distance, in centimeters, between the ball and the target. Students will determine which hand they use first by tossing a coin. The differences (nondominant – dominant) in the distances for each student are listed.28, –33, 25, 41, –14, 21, 12, –30, 17, 26, 32, 27, –25, 18, 10, 22, –19, 4, 31, 19

A
H Subscript 0 Baseline: mu Subscript difference Baseline = 0, H Subscript alpha Baseline: mu Subscript difference Baseline not-equals 0
Option A
B
H Subscript 0 Baseline: x Overbar Subscript difference Baseline = 0, H Subscript alpha Baseline: x Overbar Subscript difference Baseline not-equals 0
Option B
C
H Subscript 0 Baseline: mu dominant = mu nondominant, H Subscript alpha Baseline: mu dominant not-equals mu nondominant
Option C
D
H Subscript 0 Baseline: x Overbar dominant = x Overbar nondominant, H Subscript alpha Baseline: x Overbar dominant not-equals x Overbar nondominant
Option D
5

Chuck wants to know which brand of tire, A or B, lasts longer on cars. He chooses 32 cars and puts brand A on one side of the car and brand B on the other side. The side that receives brand A is determined by a coin toss. After three months, Chuck measures the amount of tread on all tires to determine if, on average, there is a difference (brand A – brand B) in tread wear. What are the hypotheses Chuck should use?

A
H Subscript 0 Baseline: x Overbar Subscript A Baseline = x Overbar Subscript B Baseline; H Subscript alpha Baseline: x Overbar Subscript A Baseline not-equals x Overbar Subscript B
Option A
B
H Subscript 0 Baseline: mu Subscript A Baseline = mu Subscript B Baseline; H Subscript alpha Baseline: mu Subscript A Baseline not-equals mu Subscript B
Option B
C
H Subscript 0 Baseline: x Overbar Subscript difference Baseline = 0, H Subscript alpha Baseline: x Overbar Subscript difference Baseline not-equals 0
Option C
D
H Subscript 0 Baseline: mu Subscript difference Baseline = 0; H Subscript alpha Baseline: mu Subscript difference Baseline not-equals 0
Option D
6

A researcher is interested in whether parents and their children share the same opinion on topics. She selects a random sample of 31 pairs of mothers and their daughters. Each mother/daughter pair is shown a commercial and asked to rate the likelihood that they would purchase the product on a scale of 1 (not likely) to 5 (very likely). The mean difference (mother – daughter) of the ratings is 0.85 with a standard deviation of 1.59.

A
Because the P-value is less than α, there is evidence that, on average, mothers and daughters like those in the study would have different opinions about purchasing the product.
B
Because the P-value is greater than α, there is evidence that, on average, mothers and daughters like those in the study would have different opinions about purchasing the product.
C
Because the P-value is less than α, there is not sufficient evidence that, on average, mothers and daughters like those in the study would have different opinions about purchasing the product.
D
Because the P-value is greater than α, there is not sufficient evidence that, on average, mothers and daughters like those in the study would have different opinions about purchasing the product.
9

A drug manufacturing company believes it has found a new medication to alleviate pain for headache sufferers. Twenty people with chronic headaches are asked to take a placebo pill or a pill containing the new medication during their next headache episode. The pill they take is determined by a coin flip. An hour later, the participants are asked to rate their headache pain level on a scale from 1 (no pain) to 5 (severe pain). During their next headache episode, the subjects are asked to take the other pill. The difference in pain ratings (new pill – placebo) is calculated for each subject. What are the hypotheses the company should use?

A
H Subscript 0 Baseline: Mu Subscript difference Baseline = 0; H Subscript alpha Baseline: mu Subscript difference Baseline less-than 0
Option A
B
H Subscript 0 Baseline: x Overbar Subscript difference Baseline = 0, H Subscript alpha Baseline: x Overbar Subscript difference Baseline less-than 0
Option B
C
H Subscript 0 Baseline: Mu Subscript difference Baseline = 0; H Subscript alpha Baseline: mu Subscript difference Baseline not-equals 0
Option C
D
H Subscript 0 Baseline: x Overbar Subscript difference Baseline = 0, H Subscript alpha Baseline: x Overbar Subscript difference Baseline not-equals 0
Option D

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